-3x^2-26x=16

Solution for -3x^2-26x=16 equation:

-3x^2-26x=16

We move all terms to the left:

-3x^2-26x-(16)=0

a = -3; b = -26; c = -16;
Δ = b2-4ac
Δ = -262-4·(-3)·(-16)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-22}{2*-3}=\frac{4}{-6}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+22}{2*-3}=\frac{48}{-6}
=-8
$